35个必掌握SQL语句,一口气全学完!
数据定义语言(DDL)
1.创建数据库:
CREATE DATABASE example_db;
2.删除数据库:
DROP DATABASE example_db;
3.创建表:
CREATE TABLE employees(
employee_id INT PRIMARY KEY,
name VARCHAR(100),
age INT,
department_id INT
);
4.删除表:
DROP TABLE employees;
5.添加列:
ALTER TABLE employees ADD email VARCHAR(255);
6.删除列:
ALTER TABLE employees DROP COLUMN email;
7.修改列:
ALTER TABLE employees MODIFY COLUMN name VARCHAR(255);
8.重命名列:
ALTER TABLE employees RENAME COLUMN name TO fullname;
9.创建索引:
CREATE INDEX idx_employee_name ON employees(name);
10.删除索引:
DROP INDEX idx_employee_name ON employees;
11.创建视图:
CREATE VIEW department_summary AS
SELECT department_id,COUNT(*) AS
num_employees
FROM employees
GROUP BY department_id;
12.删除视图:
DROP VIEW department_summary;
13.创建主键:
ALTER TABLE employees ADD PRIMARY KEY(employee_id);
14.删除主键:
ALTER TABLE employees DROP PRIMARY KEY;
数据操作语言(DML)
15.插入数据:
INSERT INTO employees(employee_id,name,age,department_id)
VALUES(1,'John Doe',30,5);
16.更新数据:
UPDATE employees
SET name='Jane Doe'
WHERE employee_id=1;
17.删除数据:
DELETE FROM employees WHERE employee_id=1;
18.查询所有数据:
SELECT * FROM employees;
19.查询特定列:
SELECT name,age FROM employees;
20.条件查询:
SELECT * FROM employees WHERE age>30;
21.限制查询结果数量:
SELECT * FROM employees LIMIT 10;
22.查询排序:
SELECT * FROM employees ORDER BY age DESC;
23.分组统计:
SELECT department_id,COUNT(*) AS
num_employees
FROM employees
GROUP BY department_id;
24.连接查询:
SELECT employees.name,department.name
FROM employees
JOIN departments ON employees.department_id=
departments.department_id;
25.左连接查询:
SELECT employees.name,departments.name
FROM employees
LEFT JOIN departments ON
employees.department_id=
departments.department_id;
26.子查询:
SELECT name FROM employees
WHERE department_id IN(SELECT department_id FROM
departments WHERE name='IT');
27.计算总和:
SELECT SUM(salary) FROM employees;
28.计算平均值:
SELECT AVG(salary) FROM employees;
29.计算最大值:
SELECT MAX(salary) FROM employees;
30.计算最小值:
SELECT MIN(salary) FROM employees;
31.计数:
SELECT COUNT(*) FROM employees;
32.使用别名:
SELECT COUNT(*) AS total_employees FROM employees;
33.去重查询:
SELECT DISTINCT department_id FROM employees;
34.使用条件函数:
SELECT name,CASE WHEN age>=18 THEN 'Adult' ELSE 'Minor'
END AS status FROM employees;
35.使用LIKE进行模糊查询:
SELECT * FROM employees WHERE name LIKE 'j%';
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